MCAT Organic Chemistry Question 128: Answer and Explanation

Home > MCAT Test > MCAT organic chemistry practice tests

Test Information

Question: 128

8. If propanamide were treated with water, what product(s) would be observed?

  • A. Propanamide
  • B. Propanoic acid
  • C. Equal concentrations of propanamide and propanoic acid
  • D. Propyl propanoate

Correct Answer: A

Explanation:

Propanamide is an amide; as such, it is the least reactive of the carboxylic acid derivatives discussed in this chapter. Without strong acid or base, propanamide will not be able to undergo nucleophilic acyl substitution and no reaction will occur.

Previous       Next