MCAT General Chemistry Question 261: Answer and Explanation
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Question: 261
3. Which one of the salts in Table 1 has the smallest value of ∆Godiss?
- A. PbCl2
- B. MgCO3
- C. BaSO4
- D. AgCl
Correct Answer: A
Explanation:
A The important relationship between the standard state Gibbs free energy of dissolution and the solubility product constant is given in the passage:
∆Godiss = –RTlnKsp
Since the question asks for an extreme, first eliminate the two choices for Ksp in Table 1 that are the middle values (choices B and C). The ln function is similar to the log function, and can be thought of in the same way when judging relative magnitudes of ∆Godiss in the equation above. For values of Ksp > 1, the ∆Go value will be negative, and for values of Ksp < 1, the ∆Go value will be positive. Therefore, the larger value of Ksp for PbCl2 will give the smallest value for ∆Go.